7x^2+54x+99=0

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Solution for 7x^2+54x+99=0 equation:



7x^2+54x+99=0
a = 7; b = 54; c = +99;
Δ = b2-4ac
Δ = 542-4·7·99
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-12}{2*7}=\frac{-66}{14} =-4+5/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+12}{2*7}=\frac{-42}{14} =-3 $

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